BRIDGE NOTES
SOLUTIONS OF SQUEEZE HANDS [By WILLIAM SHACKLE.] The following are the solutions of the four squeeze problems published in this column last wek: — ! ■ S. 7 H. A Q J D. 7 C. 6 4 S. 43 —y I S. 9 kH. K43 a B H. 87 !D. 3 A< 7 a ' D. 10 C; 7 : *" \ C. Q JlO S. H. 6 2 D. C. A K 8 6 2 Lead in Z's hand; Y to make the last seven tricks. Hearts are trumps. Z leads hearts and finesses or covers if A plays king through A. Y leads club' 4 and takes with dummy's king, another lead of trumps taken by Y who leads his last trump. B is now forced to drop either D. 10, S. 9, or his guard in clubs, either of which is fatal. Thus Y makes his contract. Number two was:— S. A J H. D. J 4 C. 5 2 S. K Q £ 1 S. 6 H. a 't? H. 6 D. Q 5 A - - B - D. K C. JlO i *" C. 76 4 S. 5 H. 9 7 D. C. Q 8 2 Hearts are trumps. Y to lead, and make all six tricks. This is only a question of the first lead. Y leads D 4, and trumps from Dummy. Now, He vt 9■ is led, with the result that A is forced to discard either a spade, which makes A. J good for Y, or Queen of Diamonds, which makes Y's Jack good, or 10 of Clubs, which gives Z two club tricks. If he discards a club he will later be ferced to drop either a spade or diamond on Z's second round of clubs, so Y is certain to make his contract. Number three:— $ S. QlO 5 4 H. J 7 6 D. C.76 S. 98 6 J y. I S. J 7 H. 9 ! a t> I H. D. A 4 . A ' 7 a ' D.KQ7 C. 10 9 4 ______ £. K. 9 3 2 S. 5 3 H. D. J 9 3 C. A Q J 3 Hearts are trumps, Y to make the remaining nine tricks.. Dummy to lead. The play goes thus:— Z. A. Y. B 3D 4D 6H 7D J. C 4C 6C 2C 9 D AC 7 H QD J H ? If B plays a club, Z makes three tricks in clubs. If B drops Diamond King, it makes Z's Jack good, while if he plays a Spade Y makes 2 tricks in Spades. Number 4:— S. 6 H. 9 3 D. 7 6 2 C. K J 8 *4 3 2 | y. I S. QlO 9 H- 0 7 A . B .| H. Q D. 5 4 z I D. Q9 8 3 CQ6 i____.i C. 7 S. A J 7 5 H. D. A 10 C. 10 9 3 No trumps Y to lead, and YZ to make all nine tricks. Y. B. Z. • A. 2D 3D 10 D 4D 6D 8D AD 5D CK C 7 ClO CQ CJ D 9 C 9 C 6 C 8 ? A cannot spare a spade, as one less guard gives Z all four tricks in Spades, for Y could finesse through B; yet if B drops either Queen of Hearts or Queen of Diamonds, Y will hold the top card of either suit. So simple!—when one sees the solutions! _____________
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Press, Volume LXXI, Issue 21400, 16 February 1935, Page 7
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565BRIDGE NOTES Press, Volume LXXI, Issue 21400, 16 February 1935, Page 7
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