CHESS

Southland Times, Issue 22422, 8 September 1934, Page 19

CHESS

CONDUCTED BY MELVILLE MILLS. Attempt the end, and never stand tn doubt; Nothing so hard but search will find It out. , , —Herrick. PROBLEM No. 613. (By W. Langstaff.) BLACK (Six Pieces).

WHITE (Five Pieces.)

8 | 8 | lplp4 | 5p2 | 2P5 | lplpk3 | 7Q I !K2Kt2B |. White to play and mate In three moves.

PROBLEM No. 614.

By G. Stuart Green (Calcutta BLACK (Eleven Pieces.)

WHITE (Ten Pieces.) 3KRIBI I blpS | p 7 | R5Pp I 3Kt2bQ | 3kp3 | 2plKtlPl | 2qktßkt2 |. ■White to play and mate in two moves. PROBLEM No. 615. By A. Cheney. BlB|B| 4KtklP I spKtl | 8 | Q 7 I 5K2 |. While to play and mate in three moves. PROBLEM No. 616. By J. Fux (Warsaw.) 681 I 3p4 | 2p5 | lp4Rp | 2Ktk3K | r4pßl ’ | 2Q5 | lktlkt4 |. White to play and mate in two moves. NOTICE TO SOLVERS. A correspondent has asked how marks are allotted in the Solving Contest. Marks are given for every solution on the following scale: — (1) For each correct key, which is the composer's intention, of a two-mover, 10 marks; of a three-mover. 20 marks. For each further key (“Cook"), of a two-mover, 10, and of a three-mover, 20 marks. For a correct claim of “no solution," definitely made, 10 or 20 marks respectively. Details are only required with 3-movers. (2) Should a correct key be sent, and, in addition, an Incorrect claim of another key, in case of a two-mover, 10 marks, and in case of a three-mover. 20 marks will be deducted from the marking for the correct key. SOLUTIONS TO PROBLEMS. No. 601 by L. Lamerat (3-move) Key: R—Kt4. B. W. B. W. K—B4 Kt—B3(ch) K—B3 B—Kts R—Q4 B—Kt7(ch)K—B4 Kt—K3 R—B4 — — — R—Q6orß6 — — Q—Q7 else. B—Kts etc. else Correct solutions from:—E.A.L. (Inglll). W.McF. (Timaru), “Quixote" (Ingill). No. 602 by D. H. Hersom (2-movc) Key: K—B6. Correct solutions from: —E.A.L. (Ingill), W.McF. (Timaru), “Quixote” (Ingill), "Tryer" (Ingill). “Novice" (Ingill), R.L. (Ashburton). Chester (Chch). No. 603 by E. Plesnivy (3-move). Key: B—Kt6. B. W. B. W. K x Kt Kt—K3ch K—K5 B—Bs B—B4 Kt—Kt4 any B or Q Q—B4 Kt—K7 any mates R(B1)—B4 Kt—B7 any — R(87)—84 Kt—B3 any — Pxß KtxP KtxP — — — else Kt x Kt else. Q —Kt2 or — B or Q Kt—B6 mates Correct solutions: —E.A.L. (Ingill.), W. McF. (Timaru), "Quixote” (Ingill). No. 604 by A. Ellcrman (2-move). Key: B—R7. Correct solutions from:—E.A.L. (Inglll), W.McF. (Timaru), “Quixote” (Ingill). “Tryer" (Inglll), R.L. (Ashburton), “Chester” (Chch), Novice (Ingill). END-GAME No. A 76. This position occurred in the BumSchlechter game, Vienna, 1898. Black wins speedily. BLACK (Nine Pieces).

WHITE (Seven Pieces). Black to play and win. LAST WEEK’S END GAME. No. A 75. White wins: 1 Q-87, R-KKt; 2 QxPch. RxQ: 3 R-QBch, K-R2; 4 R-R6ch, KxR; 5 R-KRBCII, R-R2; 6 RxR mate. BENONI COUNTER GAMBIT. The Queen's Pawn Opening was used most in the Alekhine —Bogoljuboff match, but there were many unusual variations. In the ninth game the Benoni Counter Gambit, Bogoljuboff. departing from the line advocated in his book, had to admit defeat on the 46th move. White Black I White Black Bogol- Alek- Bogol- Alek''juboff hine juboff hine 1 P-Q4 P-QB4(a) ]25 PxQ BLACK.

WHITE. Position after White’s 25th move PxQ. 2 P-Q5 P-K4 QR-Q 1 (h) 3 P-K4 P-Q3 26 P-B4? PxP 4 P-KB4 (b) PxP 27 Kt-K3 P-B6 5B X P Q-Rsch (c) 28 P-Kt3 B-Q5 6 P-KKt3 Q-K2 29 Kt-B4 P-B4 7 Kt-QB 3 (d) 30 P-K5 PxP P-KKt4 31 PxP BxP 8 B-K3 QKt-02 32 BxP QK-KBI 9 K-B3 P-KR3 33 Rx R (ch) RX R 10 Q-Q2 (e) KKt-B3 34 P-K6 H-Kl 11 Castles Kt-Kts 35 P-K7 QB xKt 12 B-K2 (f) B-Kt2 36 Px B Bx Kt 13 KR-B 1 Ktxß 37 Rx B RxP 14 Qx Kt P-QR 3 38 P-KR3 PxP 15 Kt-Kl P-Kt4 39 K-B2 P-R7 16 QR-K 1 B-Kt2 40 R-QKtl (ch) 17 Kt-Ql R-QKt2 Castles (Q side) 41 R-KRI R-Kt7(ch) 18 B-Kt4 K-Ktl 42 Kx P RxP 19 Bx Kt (g) Rx B 43 K-Q3 K-B2 20 Q-Q2 P-Kts 44 K-K4 K-B3 21 Kt-K3 Q-K4 45 K-B5 P-R* 22 P-B3 P-KR4 46 K-Kts P-QRS 23 Kt-B5 B-KB3 Resigns 24 Q-B4 Q x Q (a) Is anything good enough—once? (b) Bogoljuboff in his book gives 4KtQB3, B-K2; 5 P-KKt3, Kt-KB 3; 6 B-Kt2, Castles; 7 KKt-K2 as the best line for White. He may have suspected Alekhine or having prepared a response: but the departure taken by White did not produce good results. , , (c) Black seeks to gain control or his K 4 and so he compels 6 P-KKt3 in order to prevent the Bishop retreating to that square when he plays . . P-KKt4. (d) White would have been better with 7 Kt-KB2, as it is not conceivable that the champion will plunge into such a line as 7 . . ... QxP (ch); 8 K-821

(e) 10 P-KR4, P-Kts; 11 Kt-Q2 (or Ktl), Kt-K4, does not promise White anything. (f) The Bishop could have been preserved by 12 B-Ktl. White’s game on the Black squares was weak later. (g) The Black Knight threatens to take up a commanding position by . . . Kt-K4 (or Kt-Kt3) and . . . Kt-85. (h) Threatening 26 . . . B-Bl with the exchange or displacement of White’s best placed piece. White is now in difficulties with no promising line available. He hopes by his next move to procure good alternative square for tire Knight at QB4, but the end is coming swiftly. EVANS GAMBIT. Arthur Dake, the young American master, was beautifully defeated in the following example of the famous old Evans Gambit. The game was played during a tour of the States. White Black WTiite Black Scott Dake Scott Dake 1 P-K4 P-K4 12 R-Kl! Ktxß(d) 2. Kt-KB 3 Kt-QB 3 13 QxKt BxKt 3 B-B4 B-B4 14 Qx B P-KR3 (e) 4P-OKU BxKtP IS RxKtchl K. X R 5 P-B3 B-R4 16QxQBP(f) Q-Q3 6 P-Q4 PxP 17 B-R3! Qxß 7 Castles PxP (a) 18 R-Klch K-B3 8 Q-Kt3 Q-B3 19 Q-KB4ch K-Kt3 9 P-“KS Q-Kt3 20 QxPchl KxKt 10 Kt X P KKt-K2 21 R-K5 ch 11 Kt-KKt5 (b) Resigns (g) I ’ KtxP(c) (a) The so-called "Compromised Defence,” good enough if one knows all about it. (b) B-R3, the usual move, is much stronger. However, the text had the advantage of surprising Mr Dake. i (c) Too dangerous. He should solidify with Castling. (d) The following exchanges still leave him in difficulty. Good alternatives are hard to find; to meet White’s main threat of R x Kt. followed by B x Pch. For example, P-KR3, 13. RxKt PxKt, 14. Kt-Q5 would not suit Black. (e) If P-QB3, 15. Q-K5 Q-83. 16. B-R3. and the Black Kt will fall. If Q-KB3, 15. B-R3 is playable, for if then QxQ, 16. Rx Kt ch K-81, 17. QR-K 1 will finish Black, whose best fifteenth move is Castles. (f) All this is splendid. Black vainly tries to stop B-R3. If PxKt. 17. B-R3 ch K-83, 18. Q-Q6 ch K-84, 19. Q-Q5 ch K-83, 20. Q-Q4 ch K-84, 20. P-Kt4 ch and then the R comes along. | (g) He is mated in two more moves.