CHESS

Southland Times, Issue 21431, 27 June 1931, Page 15

CHESS

CONDUCTED BY MELVILLE MILLS. Attempt the end, and never stand In doubt; Nothing’s so hard but search Will 2nd It out. -Herrick. All correspondence in connection with th» column should be addressed to the Ches Editor, Southland Times, Invercargill. PROBLEM No. 357. By Brian Harley. BLACK (Four Pieces).

WHITE (Two Pieces). White plays and mates in two moves. 8 | 8 | 8 | 4Q3 | 8 | oplkt | 8 | sKbk |

PROBLEM No. 358. By T. C. Evans. Dedicated to Alain C. White. BLACK (Twelve Pieces).

WHITE (Nine Pieces). White plays and mates in two moves. B 7 | b2Kt3p | rp2Rlpr | p2Kt3p | P2k3P | IPI P 4 | kt2B2ktl | 3K4 |. PROBLEM No. 359. By Brian Harley. BLACK (Ten Pieces).

WHITE (Six Pieces). White plays and mates in three moves. 285 | 8 | K4p2 I p2kpKtpl | Ktpkt4R | 3prlktl | 8 | 3Q4.

SOLUTIONS TO PROBLEMS. No. 345 by Brian Harley (2 move). Key: R—KTB. White self interference followed by line evacuation. There are duals unfortunately, but a stalemate in B x Q. Details: If Q—B4 Kt—KG Q—K2 Kt-Qn Q x P B—QO Q—R3 R—Q7 Q—KI P x—QKt Q x R Q-QB2 Correct solutions from: E.A.L. (Ingill.), W.McF. (Timaru), “Novice” (Ingill.), “Quixote” (Ingill.), R.L. (Timaru), R.G. W. (Greenhills). No. 346 by Dr. E. Palkoko' (2 move). Key: R—Kt6. An interesting problem with a pretty discovered check in the P —KB4 line. There are four mates in this problem, which did not present serious difficulties to solvers. Details: If B x Q R—KBG P—KB4 P x P e.p. B—KKto P—KG Kt—Q4 P-KG Kt—B6 R—KBG P x R Q—BS Correct solutions from. E.A.L. (Ingill.), W.McF. (Timaru), “Quixote” (Ingill.), R. G.W. (Greenhills), “Novice” (Ingill.), R.L. (Timaru). No. 347 by Brian Harley (3 move). Key; Kt—Q4. The threat is that on Q —K6 (ch), the King moves and the Bishop mates. A sacrificial key leading to four model mates, but there arc duals after the other Black Bishop moves. Some good tries in this problem. Details: If

Correct solutions from: E.A.L. (Ingill.), W.McF. (Timaru), “Quixote” (Ingill./. WOMEN AT PLAY. From the French Women’s Championship. White. Black. Mme. Pape. Mms. Freeman. 1 P—Q4 Kt—Kß3 2 Kt—Kß3 P—Q4 3 B—B4 P—B3 4 P—K3 Q—Kt 3 5 B—Q3 (a) Q x KtP 6 QKt—Q2 Q—Kt 3 7 Castles P—K3 8 P—K4! P x P 9 Kt x P Kt x Kt 10 B x Kt Kt—Q2 11 Q-K2 Kt—B3 12 B-Q3 B—K2 13 B—K5 Castles 14 Kt—Kto (b) P—Kt3 (c) 15 Q—B3 Q—QI 16 Q-R3 P-KR4 (d) 17 P—Kt4! Kt x P (e) 18 Q x P (f) Resigns (a) A good sacrifice. The P is not worth the trouble that follows, but Black must take it, or confess an error. (b) All excellent, giving her opponent no rest. B x Kt is the immediate threat. (c) Or P—KR3, 15. B x Kt B x B, 16. Kt—R7 KR moves, 18. Kt x B ch, etc. With due care, White should succeed against a weak K side. (d) If Kt—R4, 17. Kt XRP R—KI (K x Kt, 18. Q x Kt(ch), 18. P—Kt4 Kt—Kt2 (Kt—B3, 19. Kt—Kto), 19. Q—R6 P—B3, 20. Kt—Kts! My own “brilliancy,” this, but I am sure Mme. Pape knew all about it.' (e) Px P, 18. Q—R6, and wins quickly. (f) A beautiful finish to a fine attack. P x Q, B—R7 mate.

QUEEN’S PAWN.

The following game comes from a New York tourney of twelve players, ten from the U.S.A., one from Canada (M. Fox), and . . . Capablanca from Cuba. Capablanca came first with 10 points (9 wins and 2 draws). The rising star, Kashdan, was second. White. Black. Marshall. Fox. 1 P—Q4 Kt—Kß3 2 Kt—Kß3 P-K3 3 P—B4 B—Ktsch 4 B—Q2 Q--K2 5 Q—B2 P—QKI3 (a) 6 P-K4 B x Belt 7 QKt x B P—Q3 8 P—Ko P-x P 9 P x P KKt—Q2 10 Q-K4 (b) P-QB3 11 Q —Kt4 Castles 12 B—Q3 P—KB4 13 P x P e.p. Kt x P 14 Q—R4 Q—Kta (c) 15 Castles Q QKt —Q2 16 KR-K 1 Kt—B4 17 B—B2 Kt—Rs 18 Kt—Kt3 P—QKt4 (d) 19 P—QR 3! Q-K2 (e) 20 B x Pch K—Rl 21 Kt—Ks Resigns (f) (a) B x B ch, 6. QKt x B P—B4, inducing P—K3, is a decent line. (b) Slick play, practically forcing the next four moves of Black. (e) B x P ch was threatened. Black makes an effort on the Q side. (d) Losing at once, but if he merely defends (R —KI say) there are several strong moves for White, such as 19. Kt—Ko B— Kt2, 20. Kt—Q7. (e) Q x BP, 20. R—Q4. (f) A typical Marshall.- White’s play mostly looks unsound, but actually is correct.

B. W. B. W. K x Kt B—B3(ch) K-B5 Q-K6 K—B5 B—Q2(ch) K—K4 Kt—B3 B x Kt B —Q6 (ch) K any B-B4 B x B Kt—B3(ch) K any P—K3 B else Kt—B3 (ch) K any B mates else Q-K6(ch) K r. Kt B-B3 — — K-B5 Q-K3