ANSWERS TO PROBLEMS
PdB&ISHBD NdVEUBEa 22SJ3i ' 181. By Fits. Barry, Kuri Bush :— 50x 1(36+45-r-2=40-j-4=)10=500xlO=:5000 : cubic feet x 12=60,000 feet of timber. ' 182. By O. J. 8., Crookston :— •■-*'. 13lt61?in.
183. By Chaa H. Haywood, Catiin's Eiver :— | 295-979 ft 184 By Ktz. Barry, Kuri Bush :— 8+124-2=lox (6+4^-2=) 5=50x9=460x 1728=777600v277*274=2804 4461435 gaUona. 185. By Chas. H. Haywood, Catlin's River :— 24 of eaoh. CORRECT ANSWERS. Nolens, E,oa!d Bay, 181 (answer in cubic feet), 185. i G. M. W., Kyebnrn Diggings, 183, 185. J. Whitty, Southland, 181, 184 R. T., Nugget Point, 181, 184, 185, J. F. Morris, Purakaimi, 181 (in cubic feet), 183, 185. In reference to question 183, R. T., Nugget Point, writes :— This queßtion (to me) is not sufficiently explicit. If "0. H. H." meant thnt 220 ft. was the circumference of the base, then I cive the answer to he (220-4-3 '1416) 4-2= 35-014 =radio8 of circl« and base of triangle. iv/( 2 198 + 35 -014*) = 201 072 ft the hypothenuse, and distance from circumference to top of spire.
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https://paperspast.natlib.govt.nz/newspapers/OW18791213.2.55.3
Bibliographic details
Otago Witness, Issue 1465, 13 December 1879, Page 20
Word Count
168ANSWERS TO PROBLEMS Otago Witness, Issue 1465, 13 December 1879, Page 20
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