ANSWERS TO PROBLEMS CORRECT ANSWERS.

Otago Witness, Issue 1422, 22 February 1879, Page 21

ANSWERS TO PROBLEMS

CORRECT ANSWERS.

Published February 1. 28. By J. Mitchell, Dunedin :— 4min 48sec past 10. M. J. O'Callaghan, Upper Shotover, sends the following solution :—Let x = the No. of minutes past 10 that the hour hand has passed over; then 12 x will be the number of minutes from 12 on the dial plate traversed by the minute hand, as the latter travels 12 times as quickly as the former: but the number of minutes between the hour hand and 12 is evidently equal to 10 -x; .MO -x = 12x x 10 2 2 = 24 x 10 = 25 x and x = — = — minutes = 25 5 2x 60 =24 seconds and 24 x 12=12 a=2Bßsec = 5 4min 48sec .'. the exact time is 4min 48sec past 10 o'clock. 29. By John G. Smith, Invercargill: 40. ' 30. By Witz. Barry, Kuri Bush :— Sheep 750 x 7£s = £281 5s Cows 685 x £8 = 5480 0 Bullooks 473 x £9£ = 4493 10 £10,254 15s 31. By Sigma, Shag Valley :~- 7 and 5 respectively.

Wakatip Miner, 30, 31. W. and A.8., Port Molyneux, 30, 31. M. J. O'Callaghan, Upper Shotover, 28, 29, 81. W. F. Johnson, Forest Hill, Southland, 29, 30, 81. M. G., Woodlands, 30, 31. • A. S. Fleming, Palmerston, 31. G. M. W., Kyeburn Diggings, 28, 29,30,31. We are pleased to see that there is a growing interest in the mathematical column, and we hope it will continue. M. Ross, Tapanui, your answers to Nos. 17 and 18 are correct, but they were too late.