DRIES ORDERS BY MAIL.
Cinderella and her two sisters had sent an order by mail to a drapery firm for some dress materials, and four lengths'had arrived for the three intending purchasers to make their selections. The first was ascertain number of yards in length,, and was offered at a number of shillings per yard. The second was one yard longer, and one shilling per yard cheaper than the first. The third was one yard longer than the second, and one shilling • cheaper than that lot. The fourth was' one yard "longer than the third; and again one shilling cheaper than the third. If the girls had bought all four lengths, the price to be paid would have been £11. The eldest sister took the longest piece, the second took the shortest piece. Cinderella topk one of. the two remaining pieces, and Had to wrap' up the fourth one and return, it. How', much did Cinderella pay for what she purchased. ARMCHAIR PROBLEM. I saw-: two boys on the tram with their mother, and it was obvious -that they were brothers, but it was difficult to estimate what ■ -their ages might be. My friend, who knows the family well, tells me that the names are George and Peter. In seven years time George's age will be just twice as much as Peter's age was four years ago. Is it possible to say which is th« elder of these two boys? . SOLUTIONS. Puzzle in Words.—Reset. Steer, Tin. Interest. ■ Cattle. —One man has 132 animals on the block, the other has _66 there, and is about to turn out 18 more. .' Ages.—The only reasonable; solution is. that which makes the child's age 3. Therefore the uncle and aunt are^ aged 27 and 30, and the mother must be 34 years old, so that she is the eldest of the three adults. Armchair Problem.—lt' is ■ obvious' that Claud and Doris went together, because these are the only two names with the same number of letters. Arthur did not go with Amy or with his sister, • therefore he went with Caroline. Bill could not go with Beatrice, therefore he went with Amy, and Donald took Beatrice. Street Collection.—The total must have been 8s Id, of which the three parts are 2s 3d, 2s 7Jd, and 3s 2£d. There fore the least successful collector is the one whose amount included no halfpence, and we know that she is the one who is fair of face, although we cannot say which is her name.
Undated Letter.—There are 1461 days in 4 consecutive years, thus 6 times this number makes 8766 days. As the numerator is 365, the denominator must be increased so that it becomes a multiple of 73, which requires 67 days. Then count back 67 days from June 30, and the result shows April 24 to be the date required.
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Bibliographic details
Evening Post, Volume CXXIII, Issue 108, 8 May 1937, Page 28
Word Count
476DRIES ORDERS BY MAIL. Evening Post, Volume CXXIII, Issue 108, 8 May 1937, Page 28
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