THE CHESS WORLD.

Auckland Star, Volume LXVI, Issue 236, 5 October 1935, Page 13 (Supplement)

THE CHESS WORLD.

AUSTRALIAN MATCH. SEVERAL AUCKLANDERS PLAYING. Twenty-five players a side, including several Aucklanders, are playing in a match by correspondence recently commenced between the New Zealand and Australian units of the British Chess Correspondence Association. Each player has two games, playing black on one board and white on the other, The teams are:—

1 P. A Crowl (Melbourne) t. R. O. Scott (Dunedin). 2 R, F. Condon (Wayville, S.A.) y. H. R. Abbott (Christchurch). 3G. F. Mclntosh (Hurlston Park, N.S.W-) tl IL E. Fenton (Morrinsvflle). 4 L. Spinks (Toorak, Victoria) v. J. A. Barnes (New Plymouth). 5 IL Green (St. Kilda, Victoria) T. E. F. Tibbltts (Rotorua). 6F. M. Hallman (Sydney) v, W. T. McCarthy (Te Puke). 7 W. E. Roberts (Donald, Victoria) v. R. W. Park (Henderson). S J. L. Mackie (Newtown, N.S.W.) v. R. E. Bacyertz (Auckland). 9 C. V. Lowe (Caulfield, Victoria) v. M. Rogers (New Plymouth) 10 J. McCrackett (Melbourne) v. J. A. Jackson (Kerikeri). 11 J. Bendit (Wedderburn, Victoria) v. A. Howe (Auckland). 12 A Willison (Randwick, N.S.W.) v. L. J. Mitchell (Christchurch). 13 H. F. Pike (Parramatta, N.S.W.) v. Mrs. n. R. Abbott (Christchurch). 14 B. Mint (South Yarra, Victoria) v. Rev. Dr. Merrington (Dunedin). 15 Dr. E. 11. Staples (Lithgow, N.S.W.) v. C. W. Gray (Christchurch). 16 A Burr (St. Kilda, Victoria) v. Mrs. E. L. Short (Auckland). IT S. Phillips (Dubbo, N.S.W.) T. J. S. M. Lawson (Dunedin). 18 P- Glasgow (Clarkefield, Victoria) v. R. E. Williamson (Dunedin). 19 H Ambler (Ivanhoe, Vic.) v. F. Vincent W rmS OVyanga, N.S.W.) v. F. H. 21 J "a? LehmaiVcrarrlngton, Victoria) v.’ Mrs G. V. Thorpe (Auckland). ■ oo p j RutlandrManners (Marrickville, “NSW) v. W. Jackson (Auckland). 23 d’ Price (Canberra) v. W. A. Williams 24 Dn ri K. tl J.' r o l ’Dny (Melbourne) v. N. S. 25 Victoria) V. R.’ G. Wylie (Greenhills). Auckland Match. A triangular match amongst R. E. Baeyertz, D. I. Jones (champion of the Auckland Club) and lan Burry commenced this week with a game between the last-named two. When their game was adjourned Jones was two pawns up, but Burry might possibly force a draw. New Lynn Challenge. The challenge match between the New Lynn Chess Club and the Auckland Chess Club was played last Saturday night between teams of 19 a side, Auckland winning by 12 games to 7. The game in wliich Sir George Thomas defeated the Russian champion, the latter weakening his pawn position in an attempt to force an equal ending: — Sicilian Defence. White. Black. Sir George Thomas. M. Botwinnlk. L P to K 4 P to QB4 2. Kt to KB3 P to K 3 3 P to Q 4 P takes P 4. Kt takes P Kt to KB3 5. B to Q 3 (a) Kt to B 3 6. Kt takes Kt (b) QP takes Kt (e) 7. Kt to Q2 V to K 4 8. Castles Q to B2 9.. P to QKt3 B to QB4 10. B to Kt2 B to KKt5 IL B to K2 P to KR4 (d) 12. Kt to B 4 (e)’. R to Qsq 13. Q to Esq Kt to Q2 14. B takes B P takes B 15. P to Kt 4 B to K2 16. R to Qsq R to R 4 177 P to KB3 P takes P 18. R takes P . Kt to B 3 19 R takes Rch Q takes R 20. P to KR3 (f) Kt to Q2 2L P to R 3 Q to B2 22. Q to K2 (s) R to Kt 4 23. B to Bsq R to Kt 3 24. R to Q 3 P to Kt 4 257 Kt to K 3 R to Q 3 267 Kt to B 5 R takes R 277 Q takes R B to Bsq (h) 28. B to K 3 P to KU 29. Kt to R 4 Kt to Kt 3 30 B takes Kt Q takes Bch 317 K to Bsq P to R 4 32. P to B 3 Q to B2 33? Kt to B 3 B to Q 3 34. Kt to Q2 K to K2 . 35. Kt to Kt 3 P to Ro Kt to Q2 P to QB4 (1) 37. K to K2 (J) Q to Kt 3 38. Kt to Bsq Q to B 3 39. Kt to K - Q to Kt—--40. Kt to Qoch K to Bsq 41. Q to B 3 B to K2 42 Q to Kt 3 2 to, K tsq 43. Q to K 3 P takes P (k) 44. BP takes P K to Ksq 45. Q to Q 3 (1) K to Bsq 46. Kt to B 3 Q to Kt 3 47. Q takes P 0 to KtB 48. K to B 3 (m) B to R 5 49. Q to Bach , Q J? \ 50. P takes Q K to Ksq 51. Kt takes P White won (n) (a) Kt to QB3 is the usual move here. (b) If 6. B to K 3 then 6. . . .P to Q 4; 7. Kt to Q2, P to K 4 (c) This is considered to be better than KtP takes Kt. x „ (d) 11. ... B takes B; 12. Q takes B, Castles (KR) was preferable. (e) Preventing Castles (QR) and attacking the king’s pawn. (f) If Kt takes P, then Q to Kt 3, ch, followed by B takes P. If. instead, -0, B takes P, then 20. ... R takes B; 21. Kt takes R, Q to Q 5, ch and wins. (g) Threatening R takes P. (h) Probably he feared that after 27. . . . P to Kt 3: 28. Kt takes B he would be weak on the black squares. (1) In this approximately even position Black makes an attempt to win—but it turns out badly as it leaves him with a “hole” at his Q 4 (which White soon' occupies with the knight) and a weak queen's knight’s pawn. (j) Not 37. Q takes P because of 37. . . . P takes P: 38. BP takes P, Q to B, ch ; 39 K to K2, Q takes P with advantage to Black. (k) Not 38. ... P to B 5 because of 39. Q to R 6, ch. K to Ksq ; 40. Q to RB, ch, B to Bsq : 41. Kt to 86, ch, K to K2; 42. Kt to R 7 (threatening Kt takes B followed by Q takes P, ch), with advantage to White. (l) Threatening Q takes P, ch. (m) Better than 48, Q to KtB, ch, K to Kt2: 49, Q takes P, ch, B to B 3: 50, Q to Kt 3, Q to BS, with counter-chances for Black. In reply to the text move Black should have played Q to 88, after which move he could still have put up a fight. The move he makes allows White to exchange queens. (n) The remaining moves were: 51. . . . K to 02 : 52. Kt to Kt2, B to K 8 ; 53. K to Kt I, B to B 6; 54. Kt to Q 3, K to K 3; 55. Pto KR4 Bto Q 5: 56. Pto R 4. B to B 6; 57. K to 83, B to R 4 : 58. P to Kt 4. K to B 3; 59. P to R 5, P takes P; 60. P takes P, resigns. Problem (New Series) No. 2. White (6 pieces).—King at K sq, queen at. QB3, rook at QKt7, bishop at QBB, pawns at Ql>4 and Q 6. Black (3 pieces).—King at QR3, bishop at QB2. pawn at QB4. White to play and mate in two moves. Solution of Problem No. I.—P to Kt 4. ANSWERS TO CORRESPONDENTS. W. JACKSON. —The right moves, but in reverse order.