LAST WEEK’S SOLUTIONS.

Otago Witness, Issue 3994, 30 September 1930, Page 23

LAST WEEK’S SOLUTIONS.

A FREE AMBULANCE. They had 10s lOd more than the totaj donation of four guineas. “SANS” FIGURES. Y was the son of X. A man married and the wife died. If he afterwards married her sister, it may be correctly said, in the event of himself dying before his second spouse, that he married his widow’s sister, previously, of course. ’ POSSIBLY DIFFERENT. By cutting six of them into two pieces each, leaving one intact, placing it at the top, the bottom row being cut between the five and six, an arrangement can be made that will comply with the conditions imposed. FIXING THE SIZE. Approximately 19 square inches. Deduct, in turn, the length of each side, from half their sum. Multiply these, and the square root of the product the answer. A SURPLUS. The size of the boxes shows the same number of inches in their length, width, and height as the room, the number over being 144. ANSWERS TO CORRESPONDENTS. “ Ajax.”—The distance between the two places was essential, it being 200 miles. O. T. D.—lf three persons leave their hats on the rack, there are only two different ways that each can take the wrong one. With five persons, nearly 50 different ways. A problem on combinations will appear shortly. L. E. W.—(l), (2), and (3) See last Tuesday’s Otago Witness. (4) The problem stated that the whole amount was divided in the manner given, though half only “willed.” (5) Thanks, the last X should be Y, the distances being XY 330, XZ 308, and YZ 286. 4 ERRATUM. In problem “Different Ways Home,” issue September 13, 1930, the X in line 13 should read Y, the distances being as stated in reply to L. E. W. above.