"NUTS!"

Evening Post, Issue 52, 2 March 1935, Page 14

"NUTS!"

(ByC. J. Wherefore.)

INTELLECT SHARPENERS All rights reserved.

Readers with • little Ingenuity will find In thia coliimn an abundant store of tntertalnment and amusement, and the solving of the problems should provide excellent mental exhilaration. While some of me -nuts" may appear harder that others. It will be found that non» Will require a oledae-hammer to crack th«m. Address correspondence U P.O. Box 1177, Wei. linntnn.

E A DAY AT THE RACES. :d Three men, Tom, Dick, and Harry. came into town for the purpose of id having a day at the races. Tom was ie the only one who won any money, in at fact the other two were penniless and w had to apply to their friend for assist:n ance. He was sufficiently goodn- natured to divide his winnings equally is among the three, and each man then paid his own hotel bill. The three 5 e paid by Tom, Dick, and. Harry, taken in that order, were in the ratio ■y 11, 12, and 13, and when their acjs counts were settled the total left in i- hand out of Tom's dividends was £1 a 13s. No pence were included in any 3S of the sums lent. How much did Tom is win at the races? l' A TRAM FARE. Three sisters, Alice, Bertha, and Clara, went into town together, carry'j ing the same amount of money, and , Clara paid the three tram fares, be- " cause she was the only one who had ° small change. Alice'spent a quarter of her money. Bertha spent one-third ,„ of her money, but Clara spent only ' one-ninth of what she had left when 1 d she arrived in town. The result of this was that she had just sixpence more than Alice. At this stage of the proceedings the total of the money r _ possessed by the girls was £1 2s 2d. ," What was the amount of the tram d fare? ;- A SCHOOL PICNIC. >s A picnic was held for the pupils of >t a small country. school. Only five families were represented there, and c the initials of their surnames were A, c B, C, D, and E. The boys and girls i were quite willing and even anxious v to compete with one another in the sports and competitions," but sometimes the members of the different families showed some reluctance about associating with ) one another. Thus, when a high jump was proposed, only the B and E children participated, and the latter were twice as numerous as the former. The B family are all boys. Then a long jump was proposed, | and in this it was the other three families who competed, the D family being as numerous as the other two put together. The C family on their own account challenged A and B households to oppose them in a tug-of-war, and in this it was found that the same numbers of girls and boys were pulling on each side. There were nineteen children altogether at the picnic. Mr. and Mrs. A. left a little before the others, taking their offspring with them, and among the, children then remaining on the ground the numbers of boys and girls were equal. What is the size of the family of Mr. arid Mrs. A.? SUBSTITUTION AND BOOK PROBLEM. In the words given below numerals are to be written in place of the'letters, so that the result is a sum in simple addition. No two letters have the same numerical value. Then, to make a rion-mathematieal problem, change "rove" into "trove" and "verse" into "reverse," then shuffle all 16 letters and rearrange them to form the title of a book, from which they were derived. : SIFT ROVE VERSE : HELPING A PEDESTRIAN. The following problem was shown to a critical friend, who returned it with the comment that the data seemed to be incomplete. Readers will therefore be forgiven if they make the same mistake at first sight, but it is expected of them that they will look a second time and discover, not only that sufficient information has been given, but that the solution is of the simplest kind. A man, who has a car capable of keeping a uniform speed of 20 miles per hour, drives to a place at a certain distance from his home. He has so many passengers in the car that he has been compelled to refuse a lift to a friend, but he promises to return for him. The friend pan walk four miles per hour, and he leaves the starting place at the same time as the car, and is eleven and one-third miles on his way when he meets the motor- i ist coming back for him. No time has I been lost in disembarking the party at I their destination and in turning back. I How long would it have taken the pedestrian to walk all the way? A COMPETITION. A magazine published a puzzle as a competition, with a prize for finding what the promoters decided should be the correct solution. The story was that a customer at a fruit shop demanded a dozen specimens for four shillings. These were to consist of coconuts at s£d, oranges at 4|d, and pears at 3-> d. He found fault with one of the varieties supplied, so the fruiterer took these back and substituted other numbers of the other two kinds. In this way he still supplied a dozen articles for four shillings, but there were only two varieties instead of three. A certain competitor discovered a way of fulfilling the conditions and sent it in. What was his chance of obtaining the prize? SOLUTIONS. Plums. —There were 84 plums, of which 24 were stolen. Bus Driver.—On one trip: One at 3d, three at 4d, and twenty-one at sd. On the other: Two at 3d, one at 4d, and twenty-two at sd. Early Ride. —Allowing for errors of clocks, he was riding only five miles per hour, and would reach station just as train arrived. Thus he would probably succeed in catching train, but would fail in his other intention of getting some breakfast. Anagram and Rhyme.—The anagram is: Sister, resist. The endings of the lines should be: No doubt, alone, out, of his own, broke down, went wrong, frown, all along, this, motoring man, is, began. Armchair Problems.—(l) The money was one-half, plus one-quarter, plus one-eighth, plus one-sixteenth of £1, which is 18s 9d. (2) We have to find two numbers, which differ by two, such that when 180 is divided by them the quotients differ by 3. Obviously, these are 10 and 12, therefore the trams run every 18 minutes, and he wishes they ran every 15 minutes. Three Problems.—•(!) Seventeen halfpence is eleven and one-third per cent, of 12s 6d. But it is clear that this is not the right answer, because the remaining cash could not exist without at least one halfpenny. Therefore the solution is 34 halfpence in 25 shillings. (2) The critic's first question is answered with one pound, one halfcrown, one shilling, and one penny. (3) This can only be solved if it be supposed that the collection was made half a century ago, when fourpenny pieces were still in existence. Then the answer is four of each, of half crowns, two-shilling pieces, shillings, ionvpenny pieces^ and jjenniea *